Specific resistance of conductors
Question 1:
Given two lengths of metal wire, which one will have the least electrical resistance: one that is short, or one that is long? Assume all other factors are equal (same metal type, same wire diameter, etc.).
Notes:
Many analogies exist to express this concept: water through a pipe, compressed air through a hose, etc. Which pipe or hose is less restrictive: the short one or the long one?
Question 2:
Given two lengths of solid metal wire with round crosssections, which one will have the least electrical resistance: one that is smalldiameter, or one that is largediameter? Assume all other factors are equal (same metal type, same wire length, etc.).
Notes:
Many analogies exist to express this concept: water through a pipe, compressed air through a hose, etc. Which pipe or hose is less restrictive: the skinny one or the fat one?
Question 3:
What is specific resistance, symbolized by the Greek letter "rho" (r)?
Notes:
Ask your students, "Why is it important to have a quantity called specific resistance? Why don't we just compare the "resistivity" of different substances in regular units of ohms?
Question 4:
Write a single equation relating the resistance, specific resistance, length, and crosssectional area of an electrical conductor together.

Where,
R = Resistance, measured along the conductor's length
r = Specific resistance of the substance
l = Length of the conductor
A = Crosssectional area of the conductor
Followup question: algebraically manipulate this equation to solve for length (l) instead of solving for resistance (R) as shown.
Notes:
A beneficial exercise to do with your students is to analyze this equation (and in fact, any equation) qualitatively instead of just quantitatively. Ask students what will happen to R if r increases, or if l decreases, or if A decreases. Many students find this a more challenging problem than working with real numbers, because they cannot use their calculators to give them qualitative answers (unless they enter random numbers into the equation, then change one of those numbers and recalculate  but that is twice the work of solving the equation with one set of numbers, once!).
Question 5:
Examine the following specific resistance table for various metals:

Metal type r in W · cmil / ft @ 32^{o}F r in W · cmil / ft @ 75^{o}F
Zinc (very pure) 34.595 37.957
Tin (pure) 78.489 86.748
Copper (pure annealed) 9.390 10.351
Copper (harddrawn) 9.810 10.745
Copper (annealed) 9.590 10.505
Platinum (pure) 65.670 71.418
Silver (pure annealed) 8.831 9.674
Nickel 74.128 85.138
Steel (wire) 81.179 90.150
Iron (approx. pure) 54.529 62.643
Gold (99.9 % pure) 13.216 14.404
Aluminum (99.5 % pure) 15.219 16.758
Of the metals shown, which is the best conductor of electricity? Which is the worst? What do you notice about the resistivity of these metals as temperature is increased from 32^{o}F to 75 ^{o}F?

Metal type r in W · cmil / ft @ 32^{o}F r in W · cmil / ft @ 75^{o}F
Silver (pure annealed) 8.831 9.674
Copper (pure annealed) 9.390 10.351
Copper (annealed) 9.590 10.505
Copper (harddrawn) 9.810 10.745
Gold (99.9 % pure) 13.216 14.404
Aluminum (99.5 % pure) 15.219 16.758
Zinc (very pure) 34.595 37.957
Iron (approx. pure) 54.529 62.643
Platinum (pure) 65.670 71.418
Nickel 74.128 85.138
Tin (pure) 78.489 86.748
Steel (wire) 81.179 90.150
Notes:
The data for this table was taken from table 197 of the American Electrician's Handbook (eleventh edition) by Terrell Croft and Wilford Summers.
It may come as a surprise to some students to find that gold is actually a worse conductor of electricity than copper, but the data doesn't lie! Silver is actually the best, but gold is chosen for a lot of microelectronic applications because of its resistance to oxidation.
Question 6:
What is the electrical resistance of a 12gauge copper wire, 500 feet long, at room temperature?
Notes:
Ask your students to share their sources for data: values of r, crosssectional area, etc.
Question 7:
A spool holds an unknown length of aluminum wire. The size of the wire is 4 AWG. Fortunately, both ends of the wire are available for contact with an ohmmeter, to measure the resistance of the entire spool. When measured, the wire's total resistance is 0.135 W. How much wire is on the spool (assuming the spool is at room temperature)?
Notes:
This question illustrates another practical application of specific resistance calculations: how to determine the length of wire on a spool. The amount of resistance in this example is quite low, being a mere fraction of an ohm. Ask your students what kinds of problems they might encounter trying to measure such a low resistance with accuracy. Would the typical errors incurred in such a lowresistance measurement tend to make their calculation of length be excessive, or too low? Why?
Question 8:
The crosssectional dimensions of a copper "busbar" measure 8 cm by 2.5 cm. How much resistance would this busbar have, measured endtoend, if its length is 10 meters? Assume a temperature of 20^{o} Celsius.

Notes:
This question is a good review of the metric system, relating centimeters to meters, and such. It may also be a good review of unit conversions, if students choose to do their resistance calculations using English units (cmils, or square inches) rather than metric.
Students may be surprised at the low resistance figure, but remind them that they are dealing with a solid bar of copper, over 3 square inches in crosssectional area. This is one big conductor!
Question 9:
Calculate the endtoend resistance of a 20 meter length of copper wire with a diameter of 0.05 cm. Use 1.678 ×10^{6} W·cm for the specific resistance of copper.
Notes:
Nothing to comment on here  just a straightforward calculation of resistance. Students need to be careful of the centimeter dimension, though!
Question 10:
Calculate the amount of power delivered to the load resistor in this circuit:

Also, calculate the amount of power that would be delivered to the load resistor if the wires were superconducting (R_{wire} = 0.0 W).
P_{load} = 180 Watts (with superconducting wire)
Followup question: Compare the direction of current through all components in this circuit with the polarities of their respective voltage drops. What do you notice about the relationship between current direction and voltage polarity for the battery, versus for all the resistors? How does this relate to the identification of these components as either sources or loads?
Notes:
Not only is this question good practice for series circuit calculations (Ohm's and Joule's Laws), but it also introduces superconductors in a practical context.
Question 11:
Suppose a power system were delivering AC power to a resistive load drawing 150 amps:

Calculate the load voltage, load power dissipation, the power dissipated by the wire resistance (R_{wire}), and the overall power efficiency, indicated by the Greek letter ëta" (h = [(P_{load})/(P_{source})]).
 E_{load} =
 P_{load} =
 P_{lines} =
 h =
Now, suppose we were to redesign both the generator and the load to operate at 2400 volts instead of 240 volts. This tenfold increase in voltage allows just onetenth the current to convey the same amount of power. Rather than replace all the wire with different wire, we decide to use the exact same wire as before, having the exact same resistance (0.1 W per length) as before. Recalculate load voltage, load power, wasted power, and overall efficiency of this (higher voltage) system:

 E_{load} =
 P_{load} =
 P_{lines} =
 h =
 E_{load} = 210 volts
 P_{load} = 31.5 kW
 P_{lines} = 4.5 kW
 h = 87.5 %
2400 volt system:
 E_{load} = 2397 volts
 P_{load} = 35.96 kW
 P_{lines} = 45 W
 h = 99.88 %
Notes:
An example like this usually does a good job clarifying the benefits of using high voltage over low voltage for transmission of large amounts of electrical power over substantial distances.
Question 12:
The efficiency (h) of a simple power system with losses occurring over the wires is a function of circuit current, wire resistance, and total source power:

A simple formula for calculating efficiency is given here:

Where,
P_{source} = the power output by the voltage source, in watts (W)
I = the circuit current, in amperes (A)
R = the total wire resistance (R_{wire1} + R_{wire2}), in ohms (W)
Algebraically manipulate this equation to solve for wire resistance (R) in terms of all the other variables, and then calculate the maximum amount of allowable wire resistance for a power system where a source outputting 200 kW operates at a circuit current of 48 amps, at a minimum efficiency of 90%.

The maximum allowable (total) wire resistance is 8.681 W.
Notes:
A common mistake for students to make here is entering 90% as "90" rather than as "0.9" in their calculators.
Question 13:
What size (gauge) of copper wire is needed in this circuit to ensure the load receives at least 110 volts?

Notes:
Several steps are necessary to solve this problem: Ohm's Law, algebraic manipulation of the specific resistance equation, and research into wire sizes. Be sure to spend adequate time discussing this problem with your students!
The concept of a generic "load" is any component or device that dissipates electrical power in a circuit. Often, generic loads are symbolized by a resistor symbol (a zigzag line), even though they might not really be a resistor.
Question 14:
A strain gauge is a type of sensing device widely used in the aerospace industry, for testing of vehicles and mechanical components. Explain what a strain gauge does, and how it functions.

Notes:
Ask your students to relate their answers to the illustration shown in the question. How does that strangelooking device actually measure strain? How does its resistance change, and why?
Question 15:
How does the conductance (G) of a conductor relate to its length? In other words, the longer the conductor, the (fillintheblank) its conductance is, all other factors being equal.
Followup question: how does "conductance" (G) mathematically relate to resistance (R), and what is the unit of measurement for conductance?
Notes:
There are two units of measurement for conductance: the old unit (which makes perfect sense, even though your students may laugh at it, at first), and the new unit (named after a famous electrical researcher). Make sure your students are familiar with both.